Answer:Equation = x²+(y+3)²=5²Step-by-step explanation:The question is on equation of a circle in a center-radius formThe general equation is (x-h)² + (y-k)² = r² where the center is at (h,k) and the radius is rGivenpoint P=(3,1) and point Q= (-3,-7) Find the diameter PQ [tex]d=\sqrt{(X2-X1)^2 + (Y2-Y1)^2\\[/tex][tex]d= \sqrt{(-7-1)^2 + (-3-3)^2}[/tex][tex]d=\sqrt{-8^2 + -6^2}[/tex][tex]d= \sqrt{64+36} = 10[/tex]d= 10 units hence radius is 10/2 =5 unitsFind the center of the circlecenter =[ (x₁+x₂)/2, (y₁+y₂)/2]center=[ (3+-3)/2 , (1+-7)/2]center= [ 0/2 ,-6/2]center= [0,-3]Equation = x²+(y+3)²=5²